Given the code fragment:

public class Test {
public static void main(String[] args) {
StringBuilder sb = new StringBuilder(5);
String s = "";

if (sb.equals(s)) {
System.out.println("Match 1");
} else if (sb.toString().equals(s.toString())) {
System.out.println("Match 2");
} else {
System.out.println("No Match");
}
}
}

What is the result?

Question

Given the code fragment:

public class Test {
 public static void main(String[] args) {
 StringBuilder sb = new StringBuilder(5);
 String s = "";

if (sb.equals(s)) {
 System.out.println("Match 1");
 } else if (sb.toString().equals(s.toString())) {
 System.out.println("Match 2");
 } else {
 System.out.println("No Match");
 }
 }
}

What is the result?

Accepted Answer

A. Match 2

Answer

B. Match 1

Answer

C. No Match

Answer

D. A NullPointerException is thrown at runtime.

Given the code fragment: public class Test { public static void main(String[] args) { StringBuilder sb = new StringBuilder(5); String s = ""; if (sb.equals(s)) { System.out.println("Match 1"); }…

Question

Options

How the community answered

Explanation

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