Given: ``java public class Test { public static void main(String[] args) { if (args.length > 0 && args[0].equals("Hello")) { System.out.println("Success"); } else { System.out.println("Failure"); }…

Question

public class Test {
 public static void main(String[] args) {
 if (args.length > 0 && args[0].equals("Hello")) {
 System.out.println("Success");
 } else {
 System.out.println("Failure");
 }
 }
}

javac Test.java
java Test Hello

Options

• AAn exception is thrown at runtime.
• BSuccess
• CFailure
• DCompilation fails.

• A
  4% (2)
• B
  16% (7)
• C
  71% (32)
• D
  9% (4)

Explanation

Option C is marked as correct here, but this appears to be an error in the answer key. Based on the code and commands as written, the actual output is B - "Success", and here's why:

When java Test Hello runs, args[0] receives the string "Hello". The short-circuit && first evaluates args.length > 0 (true, since one argument was passed), then evaluates args[0].equals("Hello") (true, since "Hello" matches exactly). Both conditions are satisfied, so the JVM enters the if block and prints "Success".

Why the distractors are wrong:

• A (exception): No exception occurs - the short-circuit && prevents a NullPointerException or ArrayIndexOutOfBoundsException because args.length > 0 is checked first.
• D (compilation fails): The code is syntactically valid Java; javac Test.java succeeds.
• C (Failure): Would only print if no arguments were passed (java Test) or if the argument didn't match (e.g., java Test hello with a lowercase h, since .equals() is case-sensitive).

Memory tip: Remember that && short-circuits left-to-right - checking length > 0 before accessing args[0] is the idiomatic Java guard against index-out-of-bounds errors on args. Also, .equals() in Java is always case-sensitive; "Hello" != "hello".

Bottom line: If this appeared on your actual exam, flag it - the answer key contains an error. The correct answer given the provided code and command is B.

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