Given the code fragment: ``java public static void main(String[] args) { int[] arr = {1, 2, 3, 4}; int i = 0; do { System.out.print(arr[i] + " "); i++; } while (i < arr.length - 1); } `` What is the…

Question

public static void main(String[] args) {
 int[] arr = {1, 2, 3, 4};
 int i = 0;
 do {
 System.out.print(arr[i] + " ");
 i++;
 } while (i < arr.length - 1);
}

Options

• ACompilation fails.
• B1 2 3 4
• C1 2 3
• D1 2 3 4 followed by an ArrayIndexOutOfBoundsException

• A
  5% (2)
• B
  8% (3)
• C
  73% (29)
• D
  15% (6)

Explanation

Option C is correct because the loop condition i < arr.length - 1 evaluates to i < 3, causing the loop to exit when i reaches 3 - after printing arr[0], arr[1], and arr[2] (values 1, 2, 3). The do-while body always executes at least once, so it prints 1 on the first pass, then 2 and 3 on subsequent passes, and stops before printing the fourth element.

A is wrong - the code is syntactically valid Java with no compilation errors. B is wrong - printing all four elements would require the condition i < arr.length (i.e., i < 4); the -1 cuts one iteration short. D is wrong - because the condition halts the loop before i ever reaches index 3 (the last valid index), so there is no out-of-bounds access.

Memory tip: Whenever you see arr.length - 1 as a loop bound, mentally substitute the number - here 4 - 1 = 3, so the loop runs while i < 3, meaning the last printed index is 2, not 3. Train yourself to count iterations, not just read the condition literally.

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