A method is declared to take three arguments. A program calls this method and passes only two arguments. What is the results?

Question

Options

• AA compilation fails.
• BThe third argument is given the value null.
• CThe third argument is given the value void.
• DThe third argument is given the value zero.
• EThe third argument is given the appropriate falsy value for its declared type.
• FAn exception occurs when the method attempts to access the third argument.

• A
  94% (49)
• E
  4% (2)
• F
  2% (1)

Explanation

In Java (and most statically-typed compiled languages), the compiler enforces that every method call provides exactly the number of arguments matching the method's signature - passing too few arguments is a compile-time error, not a runtime one. Options B, C, D, and E are wrong because the compiler never gets the chance to run the code and assign default values; there is no implicit default-filling behavior for missing arguments in Java. Option F is wrong for the same reason - the program never reaches runtime execution, so no exception can be thrown. Memory tip: Think of the compiler as a strict gatekeeper - it checks the "guest list" (method signature) at the door before anyone enters the party (runtime); if the argument count doesn't match, you never get in.

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