Given the code fragment: 1. public class Test { 2. public static void main(String[] args) { 3. / insert code here / 4. array[0]=10; 5. array[1]=20; 6. System.out.print (array[0]+":"+array[1]); 7. }…

The correct answer is A. int[] array = new int[2]. Option A (int[] array = new int[2];) is correct because it both declares an array reference (int[] array) and instantiates it with new int[2], allocating two integer slots - exactly what's needed before assigning array[0] and array[1]. Why the distractors fail: B is invalid…

Creating and Using Arrays

Question

Given the code fragment:
public class Test {
public static void main(String[] args) {
/* insert code here */
array[0]=10;
array[1]=20;
System.out.print (array[0]+":"+array[1]);
}
}
Which code fragment, when inserted at line 3, enables the code to print 10:20?

Options

Aint[] array = new int[2];
Bint[] array; array = int[2];
Cint array = new int[2];
Dint array [2];

How the community answered

(51 responses)

A
92% (47)
B
4% (2)
C
2% (1)
D
2% (1)

Explanation

Option A (int[] array = new int[2];) is correct because it both declares an array reference (int[] array) and instantiates it with new int[2], allocating two integer slots - exactly what's needed before assigning array[0] and array[1].

Why the distractors fail:

B is invalid syntax - array = int[2]; is not legal Java; you need new int[2] to instantiate an array.
C declares array as a single int primitive, not an array; you can't index a primitive with [0] or [1].
D is not valid Java syntax at all - Java does not support C-style int array[2]; declarations with a size inside the brackets.

Memory tip: In Java, the [] belongs with the type, not the variable name, and arrays always require new Type[size] to actually exist in memory - declaration alone just creates a null reference.

Topics

#array declaration#array initialization#new keyword#syntax

Community Discussion

No community discussion yet for this question.

Full 1Z0-808 Practice