public class Product { int id; String name; public Product (int id, String name) { this.id = id; this.name = name; } } And given the code fragment: 4. Product p1 = new Product (101, "Pen"); 5…

The correct answer is C. false:true. Option C is correct because p1 == p2 compares object references, not content - p1 and p2 point to two separate Product objects in memory (created on lines 4 and 5), so == returns false. However, p1.name.equals(p2.name) compares the String values "Pen" and "Pen", which are…

Java Basics

Question

public class Product {
int id;
String name;
public Product (int id, String name) {
this.id = id;
this.name = name;
}
}
And given the code fragment:
4. Product p1 = new Product (101, "Pen");
5. Product p2 = new Product (101, "Pen");
6. Product p3 = p1;
7. boolean ans1 = p1 == p2;
8. boolean ans2 = p1.name.equals (p2.name);
9. System.out.print (ans1 + ":" + ans2);
What is the result?

Options

Atrue:true
Btrue:false
Cfalse:true
Dfalse:false

How the community answered

(29 responses)

A
14% (4)
B
7% (2)
C
76% (22)
D
3% (1)

Explanation

Option C is correct because p1 == p2 compares object references, not content - p1 and p2 point to two separate Product objects in memory (created on lines 4 and 5), so == returns false. However, p1.name.equals(p2.name) compares the String values "Pen" and "Pen", which are identical, so .equals() returns true, giving output false:true.

Why distractors fail:

A (true:true) - p1 == p2 can't be true because they are distinct objects; only p1 == p3 would be true (same reference, line 6).
B (true:false) - wrong on both sides; == is false and .equals() is true.
D (false:false) - gets == right but incorrectly assumes .equals() on two identical Strings returns false.

Memory tip: Think of == as asking "same house?" (same memory address) and .equals() as asking "same contents?" - two houses can look identical inside while still being different houses.

Topics

#Reference Equality#equals() method#== operator#Object Identity

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