What is the result? Class StaticField { static int i = 7; public static void main(String[] args) { StaticFied obj = new StaticField(); obj.i++; StaticField.i++; obj.i++; System.out.println(StaticField

The `i` variable is declared as `static`, making it a class variable. All references to `i`, whether through an object (`obj.i`) or the class itself (`StaticField.i`), access and modify the same single variable. Initially `i` is 7. `obj.i++` makes `i=8`. `StaticField.i++` makes `i=9`. `obj.i++` makes `i=10`. Thus, both `StaticField.i` and `obj.i` will print 10.

This answer incorrectly implies that `obj.i` and `StaticField.i` would hold different values after increments, failing to recognize that a static field is shared.

This answer incorrectly assumes that `obj.i` and `StaticField.i` are distinct variables after operations, which is false for a static field.

This answer incorrectly suggests that `StaticField.i` would remain 7 or that the values would diverge in a way inconsistent with a shared static variable.