Given the code fragment: System.out.println("Result: " + 2 + 3 + 5); System.out.println("Result: " + 2 + 3 * 5); What is the result?

The correct answer is C. Result: 235. System.out.println("Result: " + 2 + 3 + 5); String concatenation is produced. System.out.println("Result: " + 2 + 3 5); 35 is calculated to 15 and is appended to string 2. Result 215. To produce an arithmetic result, the following code would have to be used: System.out.println("R

Using Operators and Decision Constructs

Question

Given the code fragment:

System.out.println("Result: " + 2 + 3 + 5); System.out.println("Result: " + 2 + 3 * 5); What is the result?

Options

AResult: 10
BResult: 10
CResult: 235
DResult: 215
ECompilation fails

How the community answered

(49 responses)

A
6% (3)
B
2% (1)
C
90% (44)
D
2% (1)

Explanation

System.out.println("Result: " + 2 + 3 + 5); String concatenation is produced. System.out.println("Result: " + 2 + 3 * 5); 3*5 is calculated to 15 and is appended to string 2. Result 215. To produce an arithmetic result, the following code would have to be used: System.out.println("Result: " + (2 + 3 + 5)); System.out.println("Result: " + (2 + 1 * 5)); If the code was as follows: System.out.println("Result: " + 2 + 3 + 5"); System.out.println("Result: " + 2 + 1 * 5"); The compilation would fail. There is an unclosed string literal, 5", on each line.

Topics

#string concatenation#operator precedence#arithmetic operators

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