1Z0-803 · Question #262
Given: public class Test { public static void main(String[] args) { int ax = 10, az = 30; int aw = 1, ay = 1; try { aw = ax % 2; ay = az / aw; } catch (ArithmeticException e1) { System.out.println("In
The correct answer is C. Invalid Divisor. The code first encounters a division by zero in the try block, catching an ArithmeticException and printing "Invalid Divisor". The program then attempts the same division outside the try-catch block, leading to an unhandled ArithmeticException and termination after printing the m
Question
Given:
public class Test { public static void main(String[] args) { int ax = 10, az = 30; int aw = 1, ay = 1; try { aw = ax % 2; ay = az / aw; } catch (ArithmeticException e1) { System.out.println("Invalid Divisor"); } catch (Exception e2) { aw = 1; System.out.println("Divisor Changed"); } ay = az /aw; // Line 14 System.out.println("Succesful Division " + ay); } } What is the result?
Options
- AInvalid Divisor
- BInvalid Divisor
- CInvalid Divisor
- DInvalid Divisor
How the community answered
(20 responses)- A15% (3)
- B5% (1)
- C70% (14)
- D10% (2)
Why each option
The code first encounters a division by zero in the try block, catching an `ArithmeticException` and printing "Invalid Divisor". The program then attempts the same division outside the try-catch block, leading to an unhandled `ArithmeticException` and termination after printing the message.
This option is identical to the correct answer. The question expects the console output, and 'Invalid Divisor' is the correct text printed before program termination.
This option is identical to the correct answer. The question expects the console output, and 'Invalid Divisor' is the correct text printed before program termination.
The code first performs `aw = 10 % 2`, setting `aw` to 0. The subsequent division `ay = 30 / aw` (`30 / 0`) in the `try` block throws an `ArithmeticException`, which is caught, and "Invalid Divisor" is printed to the console. The program then proceeds to Line 14 where `ay = az / aw` is attempted again, which also results in division by zero, causing an unhandled `ArithmeticException` that terminates the program, but only after "Invalid Divisor" has been printed.
This option is identical to the correct answer. The question expects the console output, and 'Invalid Divisor' is the correct text printed before program termination.
Concept tested: Java Exception Handling Flow
Source: https://docs.oracle.com/javase/tutorial/essential/exceptions/definition.html
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