Given: What is the result?

`true true` would imply both comparisons yielded true, which is incorrect for `new String()` versus a literal.

`true false` would imply the first comparison yielded true and the second false, which contradicts standard String interning behavior.

Assuming the code compares `new String("Java") == "Java"` and then `"Java" == "Java"`. The first comparison (`new String("Java") == "Java"`) evaluates to `false` because `new String()` creates a new object in the heap, while `"Java"` refers to a literal in the string pool, thus their references are different. The second comparison (`"Java" == "Java"`) evaluates to `true` because identical string literals refer to the same object in the string pool due to interning.

`false false` would imply both comparisons yielded false, which is incorrect for two identical string literals.

Comparing String objects using `==` is valid Java syntax and does not cause a compilation failure.