Given the code fragments: What is the result?

The code fragment likely involves an instance where either a superclass method is called directly, or a subclass's overridden method explicitly invokes `super.methodName()` to execute the parent class's implementation, resulting in 'Super' being printed.

This output would only occur if a subclass's overridden method that prints 'Contract' was invoked and did not then call its superclass's method, or if there was a separate method printing 'Contract' that was executed.

There is no inherent syntax error or logical flaw suggested by the output 'Super' that would cause a compilation failure at a specific line 'n1'.

There is no inherent syntax error or logical flaw suggested by the output 'Super' that would cause a compilation failure at a specific line 'n2'.