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Oracle

1Z0-434 · Question #8

Given the following Oracle File Adapter configuration: <adapter-config name="ReadPlanBenefit" adapter="File Adapter" wsdlLocation="ReadPlanBenefit.wsdl" <connection-factory…

The correct answer is C. This configuration can be used to create an outbound business service component. D. This configuration can be used to create an inbound proxy service component. See the full explanation below for the reasoning.

Question

Given the following Oracle File Adapter configuration:

<adapter-config name="ReadPlanBenefit" adapter="File Adapter" wsdlLocation="ReadPlanBenefit.wsdl" <connection-factory location="eis/FileAdapter"/> <endpoint-interaction portType="SynchRead_ptt" operation=" SynchRead"> <interaction-spec className="oracle.tip.adapter.file.outbound.FileReadInteraction.Spec"> <property name="DeleteFile" value="false"/> <property name="PhysicalDirectory" value="/home/plan_benefit"/> <property name="FileName" value=" plan_benefit.xml"/> <property name="PhysicalArchiveDirectory" value="/home/plan_benefit/archive/> </interaction-spec> </endpoint-interaction> </adapter-config> Which two statemnts are true?

Options

  • AThe actual source directory will be specified by a property in thecomposite.xmlfile.
  • BEach file read will be moved to an archive directory after it is successfully processed.
  • CThis configuration can be used to create an outbound business service component.
  • DThis configuration can be used to create an inbound proxy service component.

How the community answered

(36 responses)
  • A
    8% (3)
  • B
    6% (2)
  • C
    86% (31)

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