As a Linux system administrator you want to check and print the names of the users having UID 500, and are not using the bash or csh shell. Which two commands would help you to do so? (Choose two.)

Question

As a Linux system administrator you want to check and print the names of the users having UID > 500, and are not using the bash or csh shell. Which two commands would help you to do so? (Choose two.)

Accepted Answer

A. awk -F: '/([^(bash|csh)])$/ {if ($3 >500) print $1}' /etc/passwd C. awk -F: '/([^(bash)]|[^(csh)])$/ {if ($3 >500) print $1}' /etc/passwd

Answer

B. awk -F: '/([(bash)]|[(csh)])$/ {if ($3 >500) print $1}' /etc/passwd

Answer

D. awk -F: '/([^(nologin)]|[^(ksh)])$/ {if ($3 >500)print$2}' /etc/passwd

As a Linux system administrator you want to check and print the names of the users having UID > 500, and are not using the bash or csh shell. Which two commands would help you to do so? (Choose two.)

Question

Options

How the community answered

Community Discussion