The EMPLOYEES table contains these columns: EMPLOYEE_ID NUMBER(4) LAST_NAME VARCHAR2 (25) JOB_ID VARCHAR2(10) You want to search for strings that contain 'SA_' in the JOB_ID column. Which SQL…

Question

Options

• ASELECT employee_id, last_name, job_id FROM employees WHERE job_id LIKE '%SA_%' ESCAPE '';
• BSELECT employee_id, last_name, job_id FROM employees WHERE job_id LIKE '%SA_';
• CSELECT employee_id, last_name, job_id FROM employees WHERE job_id LIKE '%SA_' ESCAPE "";
• DSELECT employee_id, last_name, job_id FROM employees WHERE job_id = '%SA_';

• A
  83% (34)
• B
  2% (1)
• C
  5% (2)
• D
  10% (4)

Explanation

ESCAPE identifier to search for the actual % and _ symbol Incorrect answer: B ESCAPE identifier must be use

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