Which of the following comparison operators for test work on elements in the file system? (Choose two.)

Question

Options

• A-z
• B-eq
• C-d
• D-f
• E-it

• A
  3% (1)
• B
  11% (4)
• C
  81% (30)
• E
  5% (2)

Explanation

Options C (-d) and D (-f) are the correct answers because they operate directly on the file system: -d checks whether a given path exists and is a directory, while -f checks whether a path exists and is a regular file. Both are standard test (or [[ ]]) operators used in shell scripts to validate filesystem entries before acting on them.

Why the distractors are wrong:

• A (-z) is a string operator that tests whether a string has zero length - it has no awareness of the file system.
• B (-eq) is a numeric/integer comparison operator (equal) used to compare two numbers, not file paths.
• E (-it) is simply not a valid test operator at all.

Memory tip: Think of the file system operators as starting with letters that hint at what they test - -d for directory, -f for file, -e for exists, -r/-w/-x for read/write/execute. If an operator sounds like a string or math term (-z = zero-length, -eq = equal), it's not about the file system.

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