Given a log file loga.log with timestamps of the format DD/MM/YYYY:hh:mm:ss, which command filters out all log entries in the time period between 8:00 am and 8:59 am?

The correct answer is E. grep -E `:08:[0-9]+:[0-9]+' loga.log. You've hit your Sonnet limit · resets Jun 8, 9am (UTC)

GNU and Unix Commands

Question

Given a log file loga.log with timestamps of the format DD/MM/YYYY:hh:mm:ss, which command filters out all log entries in the time period between 8:00 am and 8:59 am?

Options

Agrep -E `:08:[09]+:[09]+' loga.log
Bgrep -E `:08:[00]+' loga.log
Cgrep -E loga.log `:08:[0-9]+:[0-9]+'
Dgrep loga.log `:08:[0-9]:[0-9]'
Egrep -E `:08:[0-9]+:[0-9]+' loga.log

How the community answered

(48 responses)

A
13% (6)
B
4% (2)
C
6% (3)
D
2% (1)
E
75% (36)

Explanation

You've hit your Sonnet limit · resets Jun 8, 9am (UTC)

Topics

#grep#regular expressions#pattern matching#log filtering

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