050-696 · Question #64
050-696 Question #64: Real Exam Question with Answer & Explanation
The correct answer is D. OU=IS.OU=CORP.OU=SLC . O=DA. The context of an eDirectory object is the full container path from the object's immediate parent up to the root Organization, excluding the object itself. Based on the exhibit, JJenkins resides in IS, which is inside CORP, which is inside SLC, within organization DA.
Question
Exhibit
Options
- AOU=IS.O=DA
- BOU= O=DA
- COU=IS.OU=SLC . O=DA
- DOU=IS.OU=CORP.OU=SLC . O=DA
- EOU=IS.OU=CORP.OU=CS.OU=SLC . O=DA
Explanation
The context of an eDirectory object is the full container path from the object's immediate parent up to the root Organization, excluding the object itself. Based on the exhibit, JJenkins resides in IS, which is inside CORP, which is inside SLC, within organization DA.
Common mistakes.
- A. OU=IS.O=DA omits the intermediate CORP and SLC organizational units that exist between IS and the Organization DA in the tree.
- B. OU=O=DA is a malformed context that collapses two separate container levels into one invalid string.
- C. OU=IS.OU=SLC.O=DA skips the CORP organizational unit that sits between IS and SLC in the correct tree hierarchy.
- E. OU=IS.OU=CORP.OU=CS.OU=SLC.O=DA inserts an extra CS organizational unit that does not exist in the path to JJenkins according to the exhibit.
Concept tested. eDirectory object context and distinguished naming
Reference. https://www.netiq.com/documentation/edirectory-92/edir_admin/data/a2iiidg.html
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